Question

the sum of the digits of a two-digit number is 14 if the number formed by reversing the digits is less than the original number by 18 find the original numbers solve using linear equation in one variable
*Solve the question for linear equation in one variable.*​

Answer 1

Step-by-step explanation:

Let digit in ones place be x

digit in tens place = (14-x)

the original digit = 10(14-x)+x

= 140-10x+x

= 140-9x

new number = 10x +(14-x)

= 10x + 14 - x

= 9x + 14

Equation :

=> (140-9x) - (9x+14) = 18

=> 140 - 9x - 9x - 14 = 18

=> 140 - 14 - 9x - 9x = 18

=> 126 - 18x = 18

=> -18x = 18-126

=> - 18x = -108

=> x = -108/-18

=> x = 6

digit in ones place = 6

digit in tens place = 14-6 = 8

original number = 10 × 8 + 6

= 80 + 6

= 86

Verification : reverse number is 68

68 + 18 = 86