Question

The sum of the digits of a two digit number is 15. If the number formed
by reversing the digits is less than the original number by 27. Find the
original number.
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Answer 1

Answer:

Step-by-step explanation:

Let tens digit of the original number be xso original number,10(x) + ... If the number formed by reversing the digits is less than the original number by 27 find the original number ... or 10x + 10x + 15 - 150 -x - x = 27 ... digits be x and (15-x), If you work it out you find that the sum of x and (15-x) is nothing but 15.

Answer 2

Answer:

Let the digit at ones place be x and the digit at tens place be y

The number is 10y + x ..............(i)

and x + y =15..................(ii)

= 10x 10y = 150 ....(iii)

number formed by reversing the digits = 10x +y

ATP

10y + x - (10x +y) =17

= 10y + x -10 x -y = 27

= 9y -9x =27

= 9(y-x)=27

= y-x =3..............(iv)

adding (ii) and (iv)

2y = 18

= y=9

So as x+y=15

x = 15-9=6

Therefore the no.is 10y+x = 10x9 +6

=96

BRAINLIEST plz pzl.

Step-by-step explanation: