Question

The sum of the digits of a two digit number is 15.The number obtained by reversing the order of
the digits of the the given number exceeds the given number by 9.Find the number

Answer 1

x+y=15                 -eq 1
10y+x=10x+y+9
9y-9x=9
y-x=1                     -eq 2

 x + y = 15
-x + y = 1
      2y = 16
y=8
 put value of y in eq 1
x+8=15
x=15-8
x=7
GN = 87

Answer 2

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Let the numbers be x and y.

Therefore,

x + y = 15 ............1st eq

10y + x = 10x + y +9

9y - 9x = 9

Y - x = 1 ......................... 2nd Eq.

Now,

x + y = 15

- x + y = 1 ( 2nd equation )

=) 2y = 16

=) y = 8

Then, put the value of y in the equation.

we get,

x + 8 = 15

=) x = 15 - 8

=) x = 7

Two digit no. is 87

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