The sum of the digits of a two digit number is 5. On adding 27 to the number, it's digits are reversed. Find the original number
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Answer:
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Step-by-step explanation:
let the 2 digit number be 10x+y (the digits are x , y)
so, x+y =5 →(eq.1)
10x +y +27 = 10y +x→(eq.2)
⇒10x -x +27 =10y -y
⇒9y - 9x =27
⇒y-x = 27/9 =3 →(eq.3)
subtracting (eq.1) from (eq.2)
⇒ (x +y = 5)-( -x +y= 3)
⇒2x =8 ∴x=4
substitute x =4 in (eq.1)
x+y =5
∴y=1
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