Question

the sum of the digits of a two-digit number is 6 if the digit is interchanged the new number the new number formed is 18 less than the original two digit numbers

Answer 1

☆Hello friend☆

Let's the original number be 10x+y
Reversed number = 10y+x

10x+y-18= 10y+x
10x+y-10y-x=18
9x-9y=18
Each getting 2

x - y = 2 _____(1)

x + y = 6 _____(2)

Adding both equation

2x = 8
x= 8/2 , x= 4

Putting x value in 1st equation,

4 - y= 2
-y = 2 - 4
-y = -2 , minus get cancelled out

y= 2

So original number was 10x+y,10× 4+2
= 42

Hope it helps

☺☺☺