The sum of the digits of a two-digit number is 7 . If the digits are reversed ,and the new number is increased by 3 ,then it equals to 4 times original number. what is the original number.
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Answer:
the original number is 16
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Answered by
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Answer:
Step-by-step explanation:
let the two digit number be 10a+b
a + b= 7
a = 7 - b
10b + a +3 = 4 (10 a + b )
10b + a +3 = 40a + 4b
10b -4b +3 = 40a - a
6b + 3 = 39a
put the value of a
39 (7-b) - 6b = 3
273 - 39b - 6b
273 - 3 = -39 - 6b
270 = 45 b
270/45 = b
b = 6
a = 7-6
a = 1
original number = 10 + b
= 10(1)+6
= 10+6
= 16
answer = 16
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