Math, asked by ivsrajni, 4 months ago

The sum of the digits of a two-digit number is 7 . If the digits are reversed ,and the new number is increased by 3 ,then it equals to 4 times original number. what is the original number.


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Answers

Answered by gokhrushreya3116
1

Answer:

the original number is 16

Attachments:
Answered by Anonymous
1

Answer:

Step-by-step explanation:

let the two digit number be 10a+b

a + b= 7

a = 7 - b

10b + a +3 = 4 (10 a + b )

10b + a +3 = 40a + 4b

10b -4b +3 = 40a - a

6b + 3 = 39a

put the value of a

39 (7-b) - 6b = 3

273 - 39b - 6b

273 - 3 = -39 - 6b

270 = 45 b

270/45 = b

b = 6

a = 7-6

a = 1

original number = 10 + b

= 10(1)+6

= 10+6

= 16

answer = 16

hope it helps

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