Question

The sum of the digits of a two‐digit number is 7. The number obtained by interchanging the digits exceeds the original number by 27. Find the number.

Follow for follow. ​

Answer 1

Answer:

let digit at ones place=x and

digit at tens place=y

So, the number will be 10y+x

x+y=7 ....(1)

reverse digit will be represented as, 10x+y

So,

(10x+y)-(10y-x)=27

9x-9y=27

x-y=3 ....(2)

Adding equation (1) and (2)

2x=10

x=5

substituting in equation (1)

y=7-5

=2

Thus, the number will be 25