Question

the sum of the digits of a two digit number is 7 . the number obtained by interchanging the digits exceeds the the original number by 27 .Find the number.

Answer 1

let the no.be 10x+y

therefore 10x+y=27

now u can solve

Answer 2

the sum of two numbers is 7
let the first number be x
the number exceeded its 27=x+27
x+x+27=7
2x+27=7
2x=7-27
2x=-20
x=-20/2=-10
the first number be -10
the second number=-10+27=17
-10+17=7