The sum of the digits of a two-digit number is 7. when the digits are reversed the number is decreased by 9, find the number.
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45 is the answer,hope it is useful ,sry it is wrong
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Heyy !
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Let the two numbers x and y
Original number = x+10y
Sum of two digits => x+ y = 7 ___________(1)
Also x= 7-y__________________________(2)
ATQ
10x+y = x+10y-9
10x-x = 10y-y-9
9x = 9y-9
DBS By 9 we get,
x= y-9______________________________(3)
By (2) and (3) We get ,
7-y = y- 9
2y = 16
y = 8
____________________________________________________________
Put Value of y in equation (3) we get
X= 8 - 9
= -1
Number is -1+10 X 8
81
_________________________________________________________
Let the two numbers x and y
Original number = x+10y
Sum of two digits => x+ y = 7 ___________(1)
Also x= 7-y__________________________(2)
ATQ
10x+y = x+10y-9
10x-x = 10y-y-9
9x = 9y-9
DBS By 9 we get,
x= y-9______________________________(3)
By (2) and (3) We get ,
7-y = y- 9
2y = 16
y = 8
____________________________________________________________
Put Value of y in equation (3) we get
X= 8 - 9
= -1
Number is -1+10 X 8
81
Anonymous:
ummm wrong sorry ---_-
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