The sum of the digits of a two digit number is 8 and the difference between the number andthat formed by reversing the digits is 18. Find the number.
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Given:-
- The sum of the digits of a two digit number is 8 and the difference between the number andthat formed by reversing the digits is 18.
To find:-
- Find the number.
Solution:-
Let the unit place digit be x
And tens place digit be y
No. Formed by x and y = 10y+x
Now, no. Obtained by reversing digits = 10x+y
=> (10y+x) - (10x+y) = 18
=> 10y+x-10x-y= 18
=> 9y-9x = 18
=> 9(y-x) = 18
=> y-x = 18/9= 2
Now,
y+x = 8
y-x = 2
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2y. = 10
Or, y =5
=> y+x=8
=> 5+x=8
=> x= 3
The required no = 10y + x
=> 10(5)+3 = 53.
Hence, the number = 53
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