The sum of the digits of a two digit number is 8. If the number formed by reversing the digits is less than the original number by 18, find the original number.
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Answered by
48
let the unit digit be x
So tense digit (8-x)
Number =10 (8-x)+x=80-10x+x=80 -9x
now interchangeable digit we got
number =10x+8-x=9x+8
according to question
9x+8+18=80 -9x
or
9x+9x=80-26
or
18x=54
or
x=3
number = 80-9x=80-9×3=80-27=53
So tense digit (8-x)
Number =10 (8-x)+x=80-10x+x=80 -9x
now interchangeable digit we got
number =10x+8-x=9x+8
according to question
9x+8+18=80 -9x
or
9x+9x=80-26
or
18x=54
or
x=3
number = 80-9x=80-9×3=80-27=53
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6
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