The sum of the two digit number is 6. If the digits are interchanged the new number formed is 18 less than the orignal number.Find the orignal two digit number.
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Let us assume, x and y are the two digits of the two-digit number
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 6 ---------------1
Also given:
10y + x = 10x + y -18
9x – 9y = 18
x – y = 2 -------------2
Adding equation 1 and equation 2
2x = 8
x = 4
Therefore, y = 6 – x = 6 – 4 = 2
Therefore, the two-digit number = 10x + y = 10*4 + 2 = 42
The original number = 42
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