Question

The sum of the digits of a two digit number is 8 of the digits are reversed the new number is 18

Answer 1

Step-by-step explanation:

Let the unit digit = x

tens digit = y

so,

Required no =10y +x

ATQ ,

x +y =9. ...........1

9( 10y + x ) = 2( 10x + y )

90y +9x = 20x + 2y

9x - 20x = 2y - 90y

- 11x = 88y

x = 8y. .........2

from 2

x = 8y ; putting in 1

8y + y =9

9y =9

y = 1

so,

x = 8×1

= 8

number = 10y + x

= 10*1 + 8

= 10 + 8

= 18