The sum of the digits of a two digit number is 9. again nine times this number is twice the number obtained by reversing the order of digits then the number is
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Answered by
1
Let the digits be x and y.
No =10x +y
X+y=9
9 (10x +y)=2(10 y+x)
No =10x +y
X+y=9
9 (10x +y)=2(10 y+x)
Answered by
1
Hi !
Let the no:s in ten's place be "x" and the no: in unit's place be"y"
Then the original no: is 10x + y
Given ,
x + y = 9 ----> (1)
Reversed order of no:s ,:-
10y + x is the reversed no:
so , given :-
9(10x + y) = 2(10y+x)
90x + 9y = 20y + 2x
88x - 11y = 0
11 [ 8x - y) = 0
8x - y = 0 ----> (2)
(2)+ (1)
8x - y = 0
+ x + y = 9
---------------
9x = 9
x = 1
x + y = 9
1 + y = 9
y = 9 - 1
y = 8
=============================
The no: is 10x + y
10 (1) + 8
= 18
18 is the no:
Let the no:s in ten's place be "x" and the no: in unit's place be"y"
Then the original no: is 10x + y
Given ,
x + y = 9 ----> (1)
Reversed order of no:s ,:-
10y + x is the reversed no:
so , given :-
9(10x + y) = 2(10y+x)
90x + 9y = 20y + 2x
88x - 11y = 0
11 [ 8x - y) = 0
8x - y = 0 ----> (2)
(2)+ (1)
8x - y = 0
+ x + y = 9
---------------
9x = 9
x = 1
x + y = 9
1 + y = 9
y = 9 - 1
y = 8
=============================
The no: is 10x + y
10 (1) + 8
= 18
18 is the no:
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