the sum of the digits of a two digit number is 9 also nine times this number is twice the number obtained by the reversing the order of the digit find the number.
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Let the digits at tens place be X and ones place be Y.
T O
X Y
The no. becomes 10X+Y
X+Y=9 .......(1)
On reversing;
T O
Y X
The no.is 10Y+X.
9(10X+Y) = 2(10Y+X)
....solving.....
We get , y=8x......(2)
Sub (2) in (1)
X+8X =9
9X =9
X=1 & Y=8
Therefore the no is 18 & the reversed no. is 81
T O
X Y
The no. becomes 10X+Y
X+Y=9 .......(1)
On reversing;
T O
Y X
The no.is 10Y+X.
9(10X+Y) = 2(10Y+X)
....solving.....
We get , y=8x......(2)
Sub (2) in (1)
X+8X =9
9X =9
X=1 & Y=8
Therefore the no is 18 & the reversed no. is 81
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Answer:
let the digit of ten place is x and one place is y
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