Math, asked by nibeditamahantpcdc29, 1 year ago

The sum of the digits of a two digit number is 9.also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number

Answers

Answered by residentking2400
4
the answer is 18...
sorry, my handwriting is not good...
Attachments:

nibeditamahantpcdc29: It's ok... Thanku
residentking2400: your most welcome...
nibeditamahantpcdc29: I'll be happy to come back
residentking2400: yaa sure...
residentking2400: thanks...
nibeditamahantpcdc29: wlcm
Answered by xItzKhushix
13

\huge\sf{Answer}

Given :-

  • The sum of digits f a two digit number is 9.

  • Also nine times this number is twice the number obtained by reversing the order of digit.

To Find :-

  • The Number

Let the unit digit and tens digits of the number be x and y                  

Number = 10y + x                  

•Number after reversing the digits = 10x + y    

A.T.Q                       

⇒  x + y = 9 ... (i)                  

⇒  9(10y + x) = 2(10x + y)                  

⇒  88y - 11x = 0                  

⇒ -x + 8y =0 ... (ii)                  

Adding equation (i) and (ii), we get                  

⇒  9y = 9                  

⇒  y = 1 ... (iii)                  

Putting the value in equation (i), we get                  

⇒  x = 8                

Hence

the number is 10y + x = 10 × 1 + 8 = 18.

#BAL

#AnswerWithQuality

Similar questions