The sum of the digits of a two-digit number is 9. If 27 is added to it, the digits of the number get reversed. The number is
(A) 25 (B) 72 (C) 63 (D) 36
Answers
Answered by
36
Here is your solution
Given :-
The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .
Now
Let ,
x and y are the two digits of a two-digit number.
The two-digit number = 10x + y
reversed number = 10y + x
x + y = 9 ------------1
A/q
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2
Substract equation 2 from equation 1
2x = 6
x = 3✔
y = 9 - x
y= 9 - 3
y= 6✔
The two digit number = 10x + y = (10 × 3) + 6 = 36.
Hope it helps you
Given :-
The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .
Now
Let ,
x and y are the two digits of a two-digit number.
The two-digit number = 10x + y
reversed number = 10y + x
x + y = 9 ------------1
A/q
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2
Substract equation 2 from equation 1
2x = 6
x = 3✔
y = 9 - x
y= 9 - 3
y= 6✔
The two digit number = 10x + y = (10 × 3) + 6 = 36.
Hope it helps you
Answered by
1
Answer:
(d) 36 is your correct answer
Similar questions