Question

THE SUM OF THE DIGITS OF A
TWO-DIGIT NUMBER IS 9. IF 27 Is
ADDED TO IT THE DIGIT OF THE
NUMBER GETS REVERSED. WHAT IS THE
NUMBER?​

Answer 1

SoluTion :-

Let the two digits be x and y

∴ x value becomes 10x {x is in tens place}

And y is y

$\tt {x+y=9}\\\\\\\tt {10x+y+27=10y+x}\\\\\\\tt {27=10y+x-10x-y}\\\\\\\tt {27=9y-9x}\\\\\\\tt {x-y=3}$

The number is 63

Or

The number is 36

Answer 2

Step-by-step explanation:

let the digit at tenth place be x

digit at ones place be y

x+y=9

therefore, original no. 10x+ y

if 10x +y+27 = 10y + x

9x -9y= -27

9 (x-y) = -27

x-y = -3

x+y =9 /x-y= -3

2x=6

x= 3

y =6

therfore the original no. = 60+3 =63

or

value of 10y +x

30+6

36