Question

the sum of the digits of a two digit number is 9. the new number obtained by interchanging the digits exceeds the given number by 27. find the given number.​

Answer 1

TWO DIGIT NUMBER = 10X + Y

ON INTERCHANGING = 10Y +X

10X + Y -10Y - X =27

9X -9Y = 27

9(X-Y) =27

X-Y = 3

X+Y= 9

X= 6

Y =3

THUS THE NUMBER IS 10*6+3=63