The sum of the digits of a two digit number is 9.the number obtained by reversing the digits is 9 less than the original number.findthe number
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Answer:
Let the digit at once digit = x
Digit at the tens place = 9-x
Original number = x + 10(9-x)
= x-(90-10x)
= x+10x-90
= 11x-90
After reversing,
Digit at once digit = 9- x
Digit at the tens place = x
Reversed number = 9-x + 10(x)
= 9-x+10x
= 9x+9
A/q
Original number - 9 = Reversed number
=> 11x-90 - 9 = 9x+9
=> 11x - 9x = 9 + 99
=> 2x = 108
=> x = 108/2
=> x = 54
Therefore, the original number is 54
And the reversed number is 45
Step-by-step explanation:
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