Math, asked by manoharanmsi6861, 8 months ago

The sum of the digits of a two digit number is 9.the number obtained by reversing the digits is 9 less than the original number.findthe number

Answers

Answered by KumarAditya17
3

Answer:

Let the digit at once digit = x

Digit at the tens place =  9-x

Original number = x + 10(9-x)

  = x-(90-10x)

  = x+10x-90

  = 11x-90

After reversing,

Digit at once digit = 9- x

Digit at the tens place = x

Reversed number = 9-x + 10(x)

  = 9-x+10x

  = 9x+9

A/q

Original number - 9 = Reversed number

=> 11x-90 - 9 = 9x+9

=> 11x - 9x = 9 + 99

=> 2x = 108

=> x = 108/2

=> x = 54

Therefore, the original number is 54

And the reversed number is 45

Step-by-step explanation:

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