Question

. An object is falling freely from a height ‘h’ under gravity, prove
mathematically total energy at any point is a constant with graph

Answer 1

Answer:

Explanation:

Let mass be m and acceleration g:

So at height h:

Total energy=mgh +1/2 mv²

Total energy= mgh+0=mgh

Now at height H:

P.E= mg(h-H)

Now here Kinetic energy:

V²=U²+2gS

V²=0+2g(H)

V²=2A(H)

Now K.E= 1/2mv²=1/2m*2g(H)

K.E=mgH

Now total energy= mg(h-H)+mgH

Total energy= mgh

Now at point where h=H where P.E=0

So K.E=1/2m*2gh

K.E=mgh

So total energy= mgh+0= mgh

Hence total energy remains conserved.