the sum of the digits of a two digit numbers is 15.if the formed by revesing the digits is less than the original number by 27 find the original number
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suppose the digit is 10x+y
now as given,
x+y=15......eq(1)
and 10x+y - (10y+x) =27
9x-9y=27
x-y=3....eq(2)
by solving both of the above eqn.
we get x=9,y=6
thus the digit is 96.
now as given,
x+y=15......eq(1)
and 10x+y - (10y+x) =27
9x-9y=27
x-y=3....eq(2)
by solving both of the above eqn.
we get x=9,y=6
thus the digit is 96.
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✆nehajain 125
✆nehajain 125
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