Question

The sum of the digits of a two digits’ number is 12. If the new number formed by
reversing the digit is greater than the original number by 18. Find the original number.

Answer 1

Step-by-step explanation:

Let, the ten place digit =X and the one place digit =y

The two digit number is=10x + y

After reversing the digit, the two digit number will be =10y + x

Here, x+y=12 given....(1)

According to the question,

(10y + x) - (10x +y) =18

=10y+x-10x-y=18

= 9y-9x=18

=y-x=18/9=2

=y=2+x

Put the value of y in the equation 1

x+y=12

=x+2+x=12

=2x=12-2=10

=x=10/2=5

Put the value of X in y

y=2+x=2+5=7

The two digits number is

10x+y=10*5+7=50+7=57