Question

The sum of the digits of a two digitted number is 4. If the digits in the unit's place is subtracted from the digits in the ten's place, then remainder is 2 find the number
​

Answer 1

Answer:

Step-by-step explanation:

Let the digit in the ten’s place be x and that of one’s place by y.

Then x+y=4——(1)

and x-y=2——(2)

(1)+(2)—->

2x=6

x=3

(1)-(3)——>

2y=2

y=1

So the number is 31

Answer 2

Answer:

31

Step-by-step explanation:

First, since the difference of the ten's place and the unit's place is 2, we will subtract it from 4. So the answer is 2.

Next we will divide it by 2, because it is a two digit number. So 2 divided by 2 is 1.

When we analize the problem, we can conclude that T minus U is equal to 2 when Ten's Digit is T and Unit's digit is U. By that, we can also conclude that T is larger than U that's why U is equal to 1 and T is equal to U plus 2 which is 3.

T is 3

U is 1

Therefore the answer is 31