Question

The sum of the digits of a two digitted number is 4 if the digit in the unit's place is subtracted from the didit in the ten's place then remainder is 2. find the number

Answer 1

let the no in unit place be y.
and the no in tens place be x.
according to condition,
x+y=4..............(1)
x-y=2................(2)
by adding (1) and (2), we get,
x=3 and y=1
therefore the number is 31.

Answer 2

Let the tens digit number be x.
Then, ones digit number = x-2.
As per the question,
x+(x-2)=4
=>x+x-2=4
=>2x=4+2
=>2x=6
=>x=6/2
=>x=3
Then, x-2=3-2=1
Hence, the 2-digit number = 31

Check: 3+1=4

Please mark this as the brainliest answer.
GOOD LUCK.....