Question

The sum of the digits of three digit number is 8. the middle digit is thrice the sum of the other two digits. The difference between the number and the number obtained be reversing the digit is zero. What is the number
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Answer 1

Step-by-step explanation:

Let, the three no. is ( 100×x + 10×y + z).

The sum of the digits of three digit number is 8.

such that,

( x + y + z) = 8 ............ (1)

the middle digit is thrice the sum of the other two digits.

such that,

y = 3 ( x + z) ............ (2)

The difference between the number and the number obtained be reversing the digit is zero

After reversing, the new no. is ( 100×z + 10×y + x)

So, according to question,

( 100×x + 10×y + z) - ( 100×z + 10×y + x) = 0

=> ( 99x - 99z ) = 0

=> x = z........(3)

So from (1),(2)&(3) we have,

( x + y + z) = 8

=> ( x + 3x + 3z + z) = 8

=> ( 4x + 4z ) = 8

=> (4x +4x ) = 8

=> x = 1 = z

So, y = (x + z) = 2x = 2×1 = 2

Hence, x, y, z are 1,2,1 respectively.

Here you go buddy. Best of Luck

Answer 2

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