Question

the sum of the digits of two digit number is 10 the number obtained by the interchanging the digits exceeds the original number by 36 find the original number.

Answer 1

Let the tens place digit be a

And Unit place digit be b

a + b = 10 --------(1)

10a + b + 36 = 10b + a

=> 9a - 9b = - 36

=> a - b = - 4 --------(2)

Adding equation 1 and 2, we get

2a = 6

a = 3

Now, On putting the value of a in equation 1, we get

b = 7

Required number = 37

Answer 2

I hope it is correct!!!