Question

The sum of the digits of two digits number 12 . if the new number formed by revising the digit in greater than the original number by 18 find the original number. check yourself​

Answer 1

Answer:

Let x be the unit digit and y be tens digit.

Then the original number be 10x+y.

Value of the number with reversed digits is 10y+x.

As per question, we have

x+y=12 ....(1)

If the digits are reversed, the digits is greater than the original number by 18.

Therefore, 10y+x=10x+y+18 

⇒9x−9y=−18 ....(2)

Multiply equation (1) by 9, we get

9x+9y=108 ....(3)

Add equations (2)and (3),

18x=90

⇒x=5

Substitute this value in equation (1), we get

5+y=12⇒y=7

Therefore, the original number is 10x+y=10×5+7=57..

Step-by-step explanation:

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Answer 2

Answer:

57

Step-by-step explanation:

Let the digits be x (tens place) and y(units place)

$x + y = 12$

Also given

$10y + x = 10x + y + 18 \\ 9y - 9x = 18 \\ y - x = 2$

Solving these equations we get

$y = 7 \\ x = 5$

Thus the number is 57

Reverse is 75 =57+18