Question

The sum of the first 10 natural numbers which are divisible by 3​

Answer 1

Answer:

3+6+9+12+15+18+21+24+27+30 = 165

Answer 2

Answer:

sequence is 3,6,9,......,30

a = 3

d = 6-3 = 3

n = 10

Sn = n/2(2a+(n-1)d

S10 = 10/2(2(3)+(9)3)

= 5(6+27)

= 5(33)

= 165