Math, asked by anjali646, 6 months ago

The sum of the first 10 natural numbers which are divisible by 3​

Answers

Answered by 1184ashish
3

Answer:

3+6+9+12+15+18+21+24+27+30 = 165

Answered by Anonymous
2

Answer:

sequence is 3,6,9,......,30

a = 3

d = 6-3 = 3

n = 10

Sn = n/2(2a+(n-1)d

S10 = 10/2(2(3)+(9)3)

= 5(6+27)

= 5(33)

= 165

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