Question

the sum of the first 10 terms of an arithmetic progression is 155 and the sum of the first a terms of same progression is 126 then the 10 th term of the progression is​

Answer 1

Answer:

Let a be the first term and d be the common difference of the given A.P. Then,S 6 =42⟹ 26 {2a+(6−1)d}=42⟹2a+5d=14 .

Answer 2

I DON'T KNOW ANSWER

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