Question

The sum of the first 100 natural numbers is divisible by

Answer 1

The sum of the first 100 natural numbers is n(n+1)/2 .

101 is an odd number and 50 is divisible by 2.

Hence, 50*101 will be divisible by 2.

Answer 2

Answer:

The correct answer of this question is 5050

Step-by-step explanation:

Given - The sum of the first 100 natural numbers.

Find - Find the sum of the first 100 natural numbers is divisible.

Now, the sum of the n natural numbers which is $\frac{n *( n+1)}{2}$

Here, $n = 100$

Therefore, Sum = $\frac{100 * (100+1)}{2}$

= $\frac{100 * 101}{2}$

$= 5050$