Question

The total number of electrons present in 4.6 gram of sodium is

Answer 1

Atomic mass of sodium is 23 u

So, 23 g of sodium has 6.022 x10^23 atoms of sodium.

1 g of sodium has (6.022 x 10^23)/23 atoms of sodium.

4.6 g of sodium will have (6.022 x 10^23) × 4.6 /23 atoms of sodium. i.e. 12.044 x 10^22 atoms of sodium.

Atomic number of sodium = 11

Number of electrons in one atom of sodium = 11

So, number of electrons in 12.044 x 10^22 atoms of sodium = 11 x 12.044 x 10^22

= 132.484 x 10^22 electrons.