The sum of the first 16 term of an Ap is 240 and the sum of the next 4 term is 220 find the common different, find the first term and find the sixteeth term
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Sum of first n terms of an AP is given as
S=
2
n
[2a+(n−1)d]
n=20,S=−240,a=7
⇒−240=
2
20
[2×7+(20−1)d]
⇒−240=10[14+19d]
⇒−240=140+190d
⇒−190d=140+240
⇒−190d=380
⇒d=
−190
380
=−2
n
th
term of an AP =a
n
=a+(n−1)d
⇒a 24
=7+(24−1)(−2)
⇒a 24
=7−46
⇒a 24
=−39
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