The sum of the first 24 terms of the sequence whose nth term is given by an = 3 +2/
3n
than n is
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Answer:
S(24) = 672
Step-by-step explanation:
I believe your Question was,
"Find the sum of first 24 terms of the sequence of numbers whose nth term is given by an=3+2n"
Now, let the first term be a1, so n = 1
a1 = 3 + 2(1) = 5
Now, 2nd term be a2, so n = 2
a2 = 3 + 2(2) = 7
Similarly,
a3 = 3 + 2(3) = 9
a4 = 3 + 2(4) = 11
and so on.....
also, a24 = 3 + 2(24) = 51
So, A.P = 5, 7, 9, 11,........,51,..........
Now, the Sum of n terms are given by the formula,
Sn = (n/2)[a + l]
where 'n' is the number of terms, 'a' is the first term and 'l' is the last term
Now,
S(24) = (24/2)[5 + 51]
S(24) = (12) × (56)
S(24) = 672
Hope it helped and you understood it........All the best
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