Math, asked by fairdeent, 10 months ago

The sum of the first 30 terms of the arithmetic progression 1, 3, 5, 7,........ is

Answers

Answered by anantrajusharma

4

Answer:

S30 = n/2[2a+(n-1)d]

=30/2[2×1+29 × 2 ]

15 [2+58]

15×60

900

Step-by-step explanation:

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