Question

the sum of the first 7 terms of an AP is 182 . if its 4th and 17th term are in ratio 1:5 ,find the AP​

Answer 1

Answer:

Given that 4th term and 17th term in ratio 1:5.

                 (a+3d)/(a+16d) = 1/5

                 5a + 15d = a + 16d

                     d = 4a  ---- (1).

We know that sum of n terms = n/2(2a+(n-1)*d)

                        the sum of 7 terms = 7/2(2a + 6d) = 182

                                                        = 7(a + 3d) = 182

                                                             (a + 3d) = 26.

                                                             (a + 3(4a)) = 26   (from (1)

                                                            a + 12a = 26

                                                           a = 2

Substitute a = 2 in (1)

d = 8.

The Ap = 2,10,18,26,34....

hope it helps you..

Answer 2

Answer:

A.P=2,10,18,26,....

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