Question

The sum of the first 99 terms of the series 3/4+5/36

Answer 1

Answer:

A'=3/4,A 2=5/36,n= 99

d=5/36-3/4=1/18

Sn =n/2[2a+(n-1)d]

Now put the value :

99/2[2(3/4)+(99-1)1/18]

=99/2[3/2+49/9]

=99/2[27+49/18]

= 99/2[76/18]

= 209