Question

The sum of the first five terms of an A.P is 240 then find its
third term.

Answer 1

Step-by-step explanation:

(a-2d)+(a-d)+a+(a+d)+(a+2d)=240

5a=240

a=48

a+4d=240 -------1

sub a=48 in ----- 1

48+4d=240

4d=240/48

4d=5

d=5/4

sub d=5/4 &a=48 in a+2d

48+2(5/4)=55.5

• therefore t3=55.