The sum of the first n natural number is 465 find n
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Step-by-step explanation:
Let the no be n
Now, Sn= n/2(2a+(n-1)d)
465= n/2(2+(n-1)) As a=1 and d=1
930=n+n^2
=n^2+31n-30n-930=0
On solving we get n=30
Hope it helps ✌️✌️✌️
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