Question

The sum of the first n natural number is 465 find n

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the no be n

Now, Sn= n/2(2a+(n-1)d)

465= n/2(2+(n-1)) As a=1 and d=1

930=n+n^2

=n^2+31n-30n-930=0

On solving we get n=30

Hope it helps ✌️✌️✌️