the sum of the first n terms if an ap is 4n*2-3n .find the Ap and hence find its 12th term
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s=4n^2-3n
put n=1
a1=4(1)^2-3(1)=1
put n=2
a2=4(2)^2-3(2)=10
put n=3
a3=4(3)^2-3(3)=27
put n=4
a4=4(4)^2-3(4)=52
1,10,27,52,........
here it is not an ap
hope its help
put n=1
a1=4(1)^2-3(1)=1
put n=2
a2=4(2)^2-3(2)=10
put n=3
a3=4(3)^2-3(3)=27
put n=4
a4=4(4)^2-3(4)=52
1,10,27,52,........
here it is not an ap
hope its help
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