The sum of the first n terms of a AP is given by Sn=2n2+3n. find the sixteenth term of the AP
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16th term = sum of 16 yes - sum of 15 terms
so , 2×16^2 +3×16 - 2×15^2-3×15 = 16th term
110 - 45 = 65 = 16th term...
#superman
16th term = sum of 16 yes - sum of 15 terms
so , 2×16^2 +3×16 - 2×15^2-3×15 = 16th term
110 - 45 = 65 = 16th term...
#superman
Answered by
4
Sn =2n2+5n
=>s1=2(1)2+5(1)=7
=>a1=7
S2=2(2)2+5(2)=18
=>a1+a2=18
a2=18-7=11
and,
d=a1-a2=11-7
=4
nthterm of APwill be-
an=a1+(n-1)d
=7+(n-1)4
=4n+3
I HOPE THIS ANSWER WILL HELP YOU
plz don't delet this answer plz
=>s1=2(1)2+5(1)=7
=>a1=7
S2=2(2)2+5(2)=18
=>a1+a2=18
a2=18-7=11
and,
d=a1-a2=11-7
=4
nthterm of APwill be-
an=a1+(n-1)d
=7+(n-1)4
=4n+3
I HOPE THIS ANSWER WILL HELP YOU
plz don't delet this answer plz
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