Question

The sum of the first ten multiples of 6 is..​

Answer 1

Answer:

330

Sn = n/2(a+l)

Where Sn sum of n turms

n = No of terms

a= first no

l = last no

Sn = 10/2(6+60)

Sn = 330

HOPE IT HELPS......

Answer 2

hi mate

here

given : find the sum of the first ten multiples of 6 is

solution: here two ways to find answer

1)The first 10 multiples of 6 are as follows :

6 × 1 = 6

6 × 2 = 12

6 × 3 = 18

6 × 4 = 24

6 × 5 = 30

6 × 6 = 36

6 × 7 = 42

6 × 8 = 48

6 × 9 = 54

6 × 10 = 60

These are the first 10 multiples of 6.

Summing the numbers we have :

6 + 12 + 18 + 24 + 30 + 36 + 42 + 48 + 54 + 60 = 330

What is important is to know the multiples of 6.

The multiples of 6 from 1 to 10.

and

2)Ap = 6 , 12 , 18 ....

1st term, a = 6 , difference, d = 12-6=6

A*10 = 6+(10-1)6

= 6+(9)6 = 6+54 = 60

S*10 = n/2 [a+an]

= 10/2(6+60)

= 5×66 = 330

i hope it helpfull to you..