The sum of the first three terms of an application is33 if the product of the first term and third term exceeds the 2nd term by 29 find the ap
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Step-by-step explanation:let the terms be
a,a+n,a+2n
a+a+n+a+2n=33
So a+n=11
Next equation
a×(a+2n)=a+n+29
Solve the above
121-n^2=40
So n =+9,-9
So the nos
2,11,20
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