The sum of the five consecutive odd integers is 125.what will be the sum of the second largest number and the product of the largest number ana smallest number?
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Heya !!!
Here is Your Answer.
Given :
Sum of five consecutive odd intrgers is 125.
Let first one be x.
Then, Second Number = x+2
Third Number = x+4
Fourth Number= x+6, and
Fifth Number= x+8
ATQ,
x + (x+2) + (x+4) + (x+6) + (x+8) = 125
5x + 20 = 125
5x = 105
x = 21
Therefore, other consecutive integers = 23, 25, 27 and 29.
Now, the sum of the second largest number and the product of the largest number and smallest number.
Second Largest Number= 27
Largest Number = 29, and
Smallest Number= 21
So,
27 + (29×21)
= 27 + 609
= 616
Hope It Helps
Here is Your Answer.
Given :
Sum of five consecutive odd intrgers is 125.
Let first one be x.
Then, Second Number = x+2
Third Number = x+4
Fourth Number= x+6, and
Fifth Number= x+8
ATQ,
x + (x+2) + (x+4) + (x+6) + (x+8) = 125
5x + 20 = 125
5x = 105
x = 21
Therefore, other consecutive integers = 23, 25, 27 and 29.
Now, the sum of the second largest number and the product of the largest number and smallest number.
Second Largest Number= 27
Largest Number = 29, and
Smallest Number= 21
So,
27 + (29×21)
= 27 + 609
= 616
Hope It Helps
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