The sum of the five consecutive odd integers is 125.what will be the sum of the second largest number and the product of the largest number ana smallest number?
Answers
Answered by
21
Heya !!!
Here is Your Answer.
Given :
Sum of five consecutive odd intrgers is 125.
Let first one be x.
Then, Second Number = x+2
Third Number = x+4
Fourth Number= x+6, and
Fifth Number= x+8
ATQ,
x + (x+2) + (x+4) + (x+6) + (x+8) = 125
5x + 20 = 125
5x = 105
x = 21
Therefore, other consecutive integers = 23, 25, 27 and 29.
Now, the sum of the second largest number and the product of the largest number and smallest number.
Second Largest Number= 27
Largest Number = 29, and
Smallest Number= 21
So,
27 + (29×21)
= 27 + 609
= 616
Hope It Helps
Here is Your Answer.
Given :
Sum of five consecutive odd intrgers is 125.
Let first one be x.
Then, Second Number = x+2
Third Number = x+4
Fourth Number= x+6, and
Fifth Number= x+8
ATQ,
x + (x+2) + (x+4) + (x+6) + (x+8) = 125
5x + 20 = 125
5x = 105
x = 21
Therefore, other consecutive integers = 23, 25, 27 and 29.
Now, the sum of the second largest number and the product of the largest number and smallest number.
Second Largest Number= 27
Largest Number = 29, and
Smallest Number= 21
So,
27 + (29×21)
= 27 + 609
= 616
Hope It Helps
Similar questions