The sum of the frist p,q,r terms of an AP are a,b,c respectively.show that
a/p(q - r) + b/q(r-p) + c/r (p-q) =0
Answers
Answered by
3
Step-by-step explanation:
sum of n terms of AP
it is given by n/2*(2a + (n-1)*d)
where a is the first term and d is the common difference
according to the question
as AP is same , let first term be a and common difference be d
a = p/2*(2a + (p-1)*d)
a = p/2*(2a + (p-1)*d)b = q/2*(2a + (q-1)*d)
a = p/2*(2a + (p-1)*d)b = q/2*(2a + (q-1)*d)c = r/2*(2a + (r-1)*d)
substituting these value in the question
all the terms will be cancelled out resulting 0 as the answer.
#answerwithquality
#BAL
Answered by
4
Step-by-step explanation:
oe live chat wapis chahiye toh dual space app download kar aur usme brainly I'd log in karo.
This will definitely help you.
Similar questions