The sum of the interior angles of a polygon is three times the sum of its exterior angle. Find the number of sides of the polygon
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As we know that sum of exterior angles of a polygon is always 360°.
And, Sum of interior angles is given 360°*3= 1080°.
Sum of interior angles = (n-2)*180°=1080°
i.e. n= 8 sides.
And, Sum of interior angles is given 360°*3= 1080°.
Sum of interior angles = (n-2)*180°=1080°
i.e. n= 8 sides.
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Given that,
The sum of the interior angles of a polygon is three times the sum of its exterior angle.
To find,
The number of sides of the polygon.
Solution,
We know that,
The sum of interior angles of a polygon = 180(n-2), n = no of sides
The sum of exterior angles of a polygon = 360
ATQ,
180(n-2)=3(360)
180n-360=1080
180n=1080+360
180n = 1440
⇒ n = 8
So, there are 8 sides of the polygon.
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