Question

the sum of the Length breadth and depth of a cuboid is 10 cm and its diagonal is 4 root 2 cm its surface area would be​

Answer 1

$\huge\bf Given$

☞ Length, breath and depth = 10cm

☞ Diagonal = 4√2

$\huge\bf To\:find$

Surface Area = ?

$\huge\bf Answer$ $\boxed{\bf{\underbrace{\overbrace{\green{length\: of\: diagonal\: of\: cuboid\: = √l²+b²+c²}}}}}$

$\boxed{\bf{\underbrace{\overbrace{\orange{surface\: area\: of\: cuboid\: = 2(lb+bh+hl)}}}}}$

Let ,Length = l

Breath = b

Depth = h

⟶√l²+b²+c² = 4√2 … (i)

⟶l²+b²+c² = 32 … (ii)

⟶( l+b+h)² = l²+b²+h²+2lb+2bh+2lh

⟶ (10)² = 32 +2 (lb+bh+lh)

⟶100 -32 = 2 (lb+bh+lh)

⟶68 = surface area

Surface area of cuboid = 68

Look At once

Volume of the cuboid = (length × breadth × height)

Suface area of cuboid = 2 (lb+bh+lh)

Diagonal of the cuboid =√( l2 + b2 +h2)

Answer 2

Hello good evening parag hru ✨