The sum of the numbers between 1 & 100 which are exactly divisible by 3 or 5 is
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this is an que of Ap
for A.P,
Sum of n terms=n/2(2a+(n-1)d)
by this formula
sum of terms divisible by 3=1683
5=1050
both 3 and 5=225
final ans 1683+1050-225=2508
Here may be calculatn mistake.but idea is correct.check it out>>>>>
for A.P,
Sum of n terms=n/2(2a+(n-1)d)
by this formula
sum of terms divisible by 3=1683
5=1050
both 3 and 5=225
final ans 1683+1050-225=2508
Here may be calculatn mistake.but idea is correct.check it out>>>>>
mkt8995:
2508
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