the sum of the numbers lying between 10 to 100 which are divisible by 7 will be
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Step-by-step explanation:
To solve is, we shall use the following formula -
t = a + (n-1) * d
where -
t = last term,
a = first term,
n = number of terms,
d = common difference.
Here,
t = 98 (98 is the last number between 10 and 100 to be divisible by 7)
a = 14 (14 is the first number between 10 and 100 to be divisible by 7)
d = 7(since every next number is supposed to be exactly divisible by 7)
n=?
Substituting these values in the formula,
98 = 14 + (n-1) * 7
98 - 14 = (n-1) * 7
84 =( n-1) * 7
12 = n-1
n = 13
Therefore, 13 numbers between 10 and 100 are divisible by 7
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