The sum of the numerator and denominator of a fraction is 4 more than twice the denominator. If the numerator and denominator are increased by 3, they are in the ratio 2: 3. Determine the fraction.
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hope that my answer is correct
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Step-by-step explanation:
let numerator be x
and denominator be y
then x+y=4+2y
x-y-4=0-->(1)
if both numerator and denominator are increased by 3,they are in the ratio 2:3
x+3/y+3=2/3
3x+9=2y+6
3x-2y+3=0-->(2)
now,solve (1) and (2),we get
multiply equation(1) by 2
equation(1)becomes,
1*2--> 2x-2y-8=0
2-->. 3x-2y+3=0
-x-11=0
x=-11
substitute x=-11 in equation(1)to get y,
x-y-4=0
-11-y-4=0
-y=15
y=-15
therefore x=-11 and y =-15.
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